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Program to Count Number of Even and Odd Numbers in Array
Program to Count Number of Even and Odd Numbers in Array
Description:
Given an array arr[] of integers, write a program to count the number of even and odd numbers present in the array.
Example 1:
Input: arr = {1, 2, 3, 4, 5}
Output: Even: 2, Odd: 3
Explanation: There are 2 even numbers (2, 4) and 3 odd numbers (1, 3, 5) in the array.
Example 2:
Input: arr = {1, 2, 3, 4, 2}
Output: 3, Odd: 2
Explanation: There are 3 even numbers (2, 4, 2) and 2 odd numbers (1, 3) in the array.
Constraints:
The array length |arr| is at least 1 and at most 10^5.
Java Code:
public class HackerAlgo {
// Count Number of Even and Odd Numbers
public static void countEvenOddNumbers(int[] arr) {
int evenCount = 0;
int oddCount = 0;
for (int num : arr) {
if (num % 2 == 0) {
evenCount++;
} else {
oddCount++;
}
}
System.out.println("Even: " + evenCount + ", Odd: " + oddCount);
}
public static void main(String[] args) {
// Example for Count Number of Even and Odd Numbers
int[] arr1 = {1, 2, 3, 4, 5};
countEvenOddNumbers(arr1);
int[] arr2 = {1, 2, 3, 4, 2};
countEvenOddNumbers(arr2Python Code:
# Count Number of Even and Odd Numbers
def count_even_odd_numbers(arr):
even_count = sum(1 for num in arr if num % 2 == 0)
odd_count = len(arr) - even_count
print(f"Even: {even_count}, Odd: {odd_count}")
# Example usage
arr1 = [1, 2, 3, 4, 5]
count_even_odd_numbers(arr1)
arr2 = [1, 2, 3, 4, 2]
count_even_odd_numbers(arr2)C++ Code:
#include <iostream>
#include <vector>
class HackerAlgo {
public:
// Count Number of Even and Odd Numbers
static void countEvenOddNumbers(const std::vector<int>&arr) {
int evenCount = 0;
int oddCount = 0;
for (int num : arr) {
if (num % 2 == 0) {
evenCount++;
} else {
oddCount++;
}
}
std::cout<< "Even: " <<evenCount<< ", Odd: " <<oddCount<< std::endl;
}
};
int main() {
// Example for Count Number of Even and Odd Numbers
std::vector<int> arr1 = {1, 2, 3, 4, 5};
HackerAlgo::countEvenOddNumbers(arr1);
std::vector<int> arr2 = {1, 2, 3, 4, 2};
HackerAlgo::countEvenOddNumbers(arr2);
return 0JavaScript Code:
class HackerAlgo {
// Count Number of Even and Odd Numbers
static countEvenOddNumbers(arr) {
constevenCount = arr.filter(num =>num % 2 === 0).length;
constoddCount = arr.length - evenCount;
console.log(`Even: ${evenCount}, Odd: ${oddCount}`);
}
}
// Example usage
const arr1 = [1, 2, 3, 4, 5];
HackerAlgo.countEvenOddNumbers(arr1);
const arr2 = [1, 2, 3, 4, 2];
HackerAlgo.countEvenOddNumbers(arr2